.
The oxidation number of $\mathrm{S}$ in this acid is
The peroxomonosulphuric acid is . The oxidation number of $\mathrm{S}$ in this acid is
.
The oxidation number of $\mathrm{S}$ in this acid is
- $+2$
- $+4$
- $+5$
- $+6$
Solution
the oxygens in peroxide linkage i.e. $\mathrm{O-O}$ has oxidation number $=-1$ each
and in oxide linkage i.e $=\mathrm{O}$ and $\mathrm{H}-\mathrm{O}-\mathrm{S}$ it is $-2$
Let the oxidation number of sulphur be $x$.
Oxidation number of $\mathrm{H}=+1$
In $\mathrm{H}_{2} \mathrm{SO}_{5}: 2 \times 1+\mathrm{x}+3 \times(-2)+2 \times(-1)=0$ $\mathrm{x}+2-6-2=0$ or $\mathrm{x}=+6$
thus Oxidation number of sulphur in peroxomonosulphuric acid $\left(\mathrm{H}_{2} \mathrm{SO}_{5}ight)$ is $+6$.
Asked in: JEE-TOPICTESTS-CHEMISTRY