The permeability of a metal is $0.1256 \mathrm{TmA}^{-1}$. Its relative permeability will be…

The permeability of a metal is $0.1256 \mathrm{TmA}^{-1}$. Its relative permeability will be $\left(\frac{\mu_0}{4 \pi}=10^{-7}\right.$ SIunit $)(\pi=3.14)$
  1. $10^5$
  2. $3 \times 10^5$
  3. $2 \times 10^6$
  4. $10^4$

Solution

$\begin{aligned} & \mu=0.1256 \\ & \mu_0=4 \pi \times 10^{-7}=4 \times 3.14 \times 10^{-7} \\ & =12.56 \times 10^{-7} \mathrm{TmA}^{-1} \\ & \mu_{\mathrm{r}}=\frac{\mu}{\mu_0}=\frac{0.1256}{12.56 \times 10^{-7}}=10^5\end{aligned}$ /

Asked in: MHT CET 2021 (22 Sep Shift 1)

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