The periodic waves of amplitudes $A_1$ and $A_2$ pass through a region. If $A_1 > A_2$, the difference in…

The periodic waves of amplitudes $A_1$ and $A_2$ pass through a region. If $A_1 > A_2$, the difference in the maximum and minimum resultant amplitudes possible is
  1. $2A_1$
  2. $2A_2$
  3. $A_1 + A_2$
  4. $A_1 - A_2$

Solution

Maximum amplitude, $A_{\text{max}} = A_1 + A_2$ Minimum amplitude, $A_{\text{min}} = A_1 - A_2$ Difference, $A_{\text{max}} - A_{\text{min}} = A_1 + A_2 - (A_1 - A_2) = 2A_2$

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