The period of oscillation of a simple pendulum of length \(l\) suspended from the roof of a vehicle, which…

The period of oscillation of a simple pendulum of length \(l\) suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination \(\alpha\), is given by
  1. \(2 \pi \sqrt{\frac{1}{g \cos \alpha}}\)
  2. \(2 \pi \sqrt{\frac{1}{g \sin \alpha}}\)
  3. \(2 \pi \sqrt{\frac{1}{g}}\)
  4. \(2 \pi \sqrt{\frac{1}{\mathrm{~g} \tan \alpha}}\)

Solution

Hints:
\(\begin{aligned} & \mathrm{g}_{\text {eff }}=\mathrm{g} \cos \alpha \\ & \mathrm{T}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}_{\text {eff }}}} \end{aligned}\)

Asked in: TEST SERIES MHT-CET Full Test 6

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