The period of oscillation of a simple pendulum is T = 2 π L g . Measured value of L is 1 . 0   m…

The period of oscillation of a simple pendulum is T=2πLg. Measured value of L is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of 'g' will be:
  1. 1.03%
  2. 1.33%
  3. 1.30%
  4. 1.13%

Solution

T=2πℓg

g=4π2ℓT2

Δgg=Δℓℓ+2ΔTT

Δgg=1×10-31+2×0.011.95

Δgg=0.0113 or 1.13%

Asked in: JEE Main 2021 (24 Feb Shift 2)

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