The period of $\sin ^2 \theta$ is

The period of $\sin ^2 \theta$ is
  1. $\pi^2$
  2. $\pi$
  3. $2 \pi$
  4. $\pi / 2$

Solution

$\sin ^2 \theta=\frac{1-\cos 2 \theta}{2} ;$ Period $=\frac{2 \pi}{2}=\pi$

Asked in: JEE Main 2002

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