The perimeter of \(\triangle A B C\) is \(36 \mathrm{~cm}\) and its in radius is \(8 \mathrm{~cm}\). Then,…
The perimeter of \(\triangle A B C\) is \(36 \mathrm{~cm}\) and its in radius is \(8 \mathrm{~cm}\). Then, the area of the triangle is
- \(144 \mathrm{~cm}^2\)
- \(124 \mathrm{~cm}^2\)
- \(164 \mathrm{~cm}^2\)
- \(104 \mathrm{~cm}^2\)
Solution
In radius \((r)=\frac{\Delta}{S}\)
\(\begin{aligned}
\Delta & =(r \cdot s), \Delta \rightarrow \text { Area, } S \rightarrow \text { Semi-perimeter } \\
\Rightarrow \quad \Delta & =8 \times \frac{36}{2}=144 \mathrm{~cm}^2
\end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 1)
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