The percentage of pyridine C 5 H 5 N that forms pyridinium ion C 5 H 5 N + H in a 0 . 10 M aqueous pyridine…

The percentage of pyridine C5H5N that forms pyridinium ion C5H5N+H in a 0.10 M aqueous pyridine solution Kb for C5H5N=1.7×10-9 is
  1. 0.0060%
  2. 0.013%
  3. 0.77%
  4. 1.6%

Solution

C5H5N+H2OC5H5NH+OHt=0Ct=eqC1-αCαCα
Kb=Cα21-αCα2
α=KbC=1.7×10-90.1
= 1.3 × 1 0 - 4
% α=1.3×10-4×100=0.013%

Asked in: NEET 2016 (Phase 2)

Practice more Ionic Equilibria questions on Aicharya