The \% $\left(\frac{W}{V}\right)$ of $\mathrm{H}_2 \mathrm{O}_2$ in $1.5 \mathrm{~N}$ solution is

The \% $\left(\frac{W}{V}\right)$ of $\mathrm{H}_2 \mathrm{O}_2$ in $1.5 \mathrm{~N}$ solution is
  1. $3.6$
  2. $2.99$
  3. $2.55$
  4. $2.4$

Solution

We know, Normality $=2 \times M$ $\begin{aligned} & M=\frac{1.5}{2}=0.75 \\ & M=\frac{\text { mass }}{\text { mol. mass } \times V(\mathrm{~L})}\end{aligned}$ mass $=0.75 \times 34 \times \mathrm{L}$ $=25.5$ $\% \frac{W}{V}=25.5 \times \frac{100}{1000}$ $=2.55$.

Asked in: AP EAMCET 2021 (23 Aug Shift 2)

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