The percent dissociation of weak monobasic acid is $3 \%$ in its $0.02 \mathrm{M}$ solution. What is the…
The percent dissociation of weak monobasic acid is $3 \%$ in its $0.02 \mathrm{M}$ solution. What is the dissociation constant of acid?
- $9 \times 10^{-4}$
- $3 \times 10^{-2}$
- $2 \times 10^{-2}$
- $1.8 \times 10^{-5}$
Solution
$\begin{aligned} & K_a=\propto^2 C \\ & =\left(\frac{3}{100}\right)^2 \times 0.02 \\ & =1.8 \times 10^{-5}\end{aligned}$
Asked in: MHT CET 2022 (08 Aug Shift 1)
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