The peak voltage of the AC source is equal to

The peak voltage of the AC source is equal to

the rms value of the ac source
$\sqrt{2}$ times the rms value of the ac source
$\frac{1}{\sqrt{2}}$ times the rms value of the ac source
the value of voltage supplied to the circuit

Solution

RMS voltage is related to peak voltage by relation $e_{RMS} = \frac{e_{0}}{\sqrt{2}}$ .

Thus, peak voltage of the AC source is $e_{0} = \sqrt{2} e_{RMS}$ .

Asked in: NEET 2022 (Phase 1)

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