The path running around a square lawn of side $a$ has uniform width $b$ outside. The area of the path is
The path running around a square lawn of side $a$ has uniform width $b$ outside. The area of the path is
- $4b(a + b)$
- $4ab$
- $(a + 2b)^{2}$
- $2b(a + b)$
Solution
Outer side $= a+2b$. Path area $= (a+2b)^{2} - a^{2} = (a+2b-a)(a+2b+a) = 2b(2a+2b) = 4b(a+b)$.
Asked in: IMO
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