The path length of oscillation of simple pendulum of length $1 \mathrm{~m}$ is $16 \mathrm{~cm}$. its…
The path length of oscillation of simple pendulum of length $1 \mathrm{~m}$ is $16 \mathrm{~cm}$. its maximum velocity is (Take $g=\pi^2 \mathrm{~m} / \mathrm{s}^2$ )
$2 \pi \mathrm{cm} / \mathrm{s}$
$8 \pi \mathrm{cm} / \mathrm{s}$
$4 \pi \mathrm{cm} / \mathrm{s}$
$16 \pi \mathrm{cm} / \mathrm{s}$
Solution
Amplitude of SHM, $a=8 \mathrm{~cm}$
Maximum velocity is given by, $v=a \omega=a \sqrt{\frac{g}{l}}=8 \times \sqrt{\frac{\pi^2}{1}}=8 \pi \mathrm{cm} / \mathrm{s}$
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