The parametric equations of the circle $x^2+y^2+2 x-4 y-4=0$ are
The parametric equations of the circle $x^2+y^2+2 x-4 y-4=0$ are
$x=-1+3 \cos \theta, y=2+3 \sin \theta$
$x=1+3 \cos \theta, y=-2+3 \sin \theta$
$x=-1+3 \sin \theta, y=-2+3 \cos \theta$
$x=1+3 \sin \theta, y=-2+3 \cos \theta$
Solution
Given equation of circle is
$\begin{aligned}
& x^2+y^2+2 x-4 y-4=0 \\
& \Rightarrow\left(x^2+2 x+1\right)+\left(y^2-4 y+4\right)-4-5=0 \\
& \Rightarrow(x+1)^2+(y-2)^2=3^2
\end{aligned}$
$\therefore \quad$ Parametric equation of circle is
$x=-1+3 \cos \theta, y=2+3 \sin \theta$