Given equation can be written as
$\begin{aligned}
& \quad\left(x^2-\mathrm{a} x+\frac{\mathrm{a}^2}{4}\right)+\left(y^2-\mathrm{b} y+\frac{\mathrm{b}^2}{4}\right)=\frac{\mathrm{a}^2}{4}+\frac{\mathrm{b}^2}{4} \\
& \quad \Rightarrow\left(x-\frac{\mathrm{a}}{2}\right)^2+\left(y-\frac{\mathrm{b}}{2}\right)^2=\left(\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}}\right)^2 \\
& \therefore \quad \mathrm{~h}=\frac{\mathrm{a}}{2}, \mathrm{k}=\frac{\mathrm{b}}{2} \text { and } \mathrm{r}=\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}}
\end{aligned}$
$\therefore \quad$ Parametric equations of circle are $x=\frac{a}{2}+\frac{\sqrt{a^2+b^2}}{2} \cos \theta$ and
$y=\frac{\mathrm{b}}{2}+\frac{\sqrt{\mathrm{a}^2+\mathrm{b}^2}}{2} \sin \theta$