The parallel sides of a trapezium are $10$ cm and $14$ cm and the distance between them is $6$ cm. Its area…

The parallel sides of a trapezium are $10$ cm and $14$ cm and the distance between them is $6$ cm. Its area is:
  1. $48$ cm$^{2}$
  2. $60$ cm$^{2}$
  3. $72$ cm$^{2}$
  4. $84$ cm$^{2}$

Solution

Area $= \dfrac{1}{2}(\text{sum of parallel sides}) \times \text{height} = \dfrac{1}{2}(10+14)(6) = \dfrac{1}{2}(24)(6) = 72$ cm$^{2}$.

Asked in: IMO

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