The parallel sides of a trapezium are $10$ cm and $14$ cm and the distance between them is $6$ cm. Find its…
The parallel sides of a trapezium are $10$ cm and $14$ cm and the distance between them is $6$ cm. Find its area.
- $72 \text{ cm}^{2}$
- $144 \text{ cm}^{2}$
- $60 \text{ cm}^{2}$
- $84 \text{ cm}^{2}$
Solution
Area $= \dfrac{1}{2}(a+b)\cdot h = \dfrac{1}{2}(10+14)\cdot 6 = \dfrac{1}{2}\cdot 24 \cdot 6 = 72 \text{ cm}^{2}$.
Asked in: IMO
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