The parabola having its focus at (3,2) and directrix along the $y$ -axis has its vertex at
The parabola having its focus at (3,2) and directrix along the $y$ -axis has its vertex at
(2,2)
$\left(\frac{3}{2}, 2\right)$
$\left(\frac{1}{2}, 2\right)$
$\left(\frac{2}{3}, 2\right)$
Solution
Vertex of the parabola is a point which lies on the axis of the parabola, which is a line $\perp$ to the directrix through the focus, i.e., $\mathrm{y}=2$ and equidistant from the focus and directrix $\mathrm{x}=0$, so that the vertex is $\left(\frac{3}{2}, 2\right)$.
