The pair of xenon compounds which have same number of lone pairs of electrons on the central atom is

1. $\mathrm{XeO}_3, \mathrm{XeF}_6$
2. $\mathrm{XeF}_2, \mathrm{XeF}_4$
3. $\mathrm{XeF}_4, \mathrm{XeO}_3$
4. $\mathrm{XeF}_4, \mathrm{XeOF}_4$

Solution

Xe has 6 of its electrons in bonding with one lone pair, i.e. Xe will have 2 non-bonding electrons. In $\mathrm{XeF}_6$
Xe has 6 of its electrons in bonding with F. So, Xe will have 2 non-bonding electrons, i.e. 1 lone pair.

Asked in: AP EAMCET 2018 (23 Apr Shift 1)

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