The pair of straight lines represented by the equation \(3 d x^2-5 x y+\left(d^2-2\right) y^2=0\). If the…

The pair of straight lines represented by the equation \(3 d x^2-5 x y+\left(d^2-2\right) y^2=0\). If the lines are perpendicular to each other, for how many values of \(d\) this condition will be satisfied?
  1. 0
  2. 2
  3. 1
  4. 3

Solution

Given, pair of straight lines is \(3 d x^2-5 x y+\left(d^2-2\right) y^2=0\) Since, lines are perpendicular \(\Rightarrow x^2\) coefficient \(+y^2\) coefficient \(=0\) \(\begin{gathered} 3 d+d^2-2=0 \\ d^2+3 d-2=0 \\ d=\frac{-3 \pm \sqrt{9-4 \cdot(-2)}}{2 \cdot 1}=\frac{-3 \pm \sqrt{17}}{2} \\ =\frac{-3+\sqrt{17}}{2}(\text { or })=\frac{-3-\sqrt{17}}{2} \end{gathered}\) Number of possible value of \(d\) are 2 Hence, option (b) is correct.

Asked in: AP EAMCET 2020 (18 Sep Shift 2)

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