The oxidation state of $\mathrm{Cr}$ in $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_4…

The oxidation state of $\mathrm{Cr}$ in $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$is
  1. $+3$
  2. $+2$
  3. $+1$
  4. 0

Solution

$\left(\mathrm{Cr}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right)^{+}$ $X+4 \times 0+2 \times-1=1$ $\mathrm{X}=+3$

Asked in: JEE Main 2005

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