The oxidation state of $\mathrm{Fe}$ in $\mathrm{Fe}_{3} \mathrm{O}_{8}$ is

The oxidation state of $\mathrm{Fe}$ in $\mathrm{Fe}_{3} \mathrm{O}_{8}$ is
  1. $3 / 2$
  2. $4 / 5$
  3. $5 / 4$
  4. $16 / 3$

Solution

$\mathrm{Fe}_{3} \mathrm{O}_{8}$
$3 x-16=0 \Rightarrow x=\frac{16}{3}$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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