The output voltage in the following circuit is (Consider ideal diode case)
The output voltage in the following circuit is (Consider ideal diode case)
10 V
0 V
$+5 \mathrm{~V}$
$-5 \mathrm{~V}$
Solution
Here $D_1$ is reverse biased and $D_2$ is forward biased. Therefore current flow through $\mathrm{D}_{\mathrm{Q}}$ and 5 V drop on resistor. So, $V_{\text {out }}=0$