The output of following combination is same as that of

The output of following combination is same as that of
  1. AND gate
  2. OR gate
  3. NAND gate
  4. NOR gate

Solution

Considering the truth table for the given circuit, $\begin{array}{|c|c|c|c|c|} \hline \mathbf{A} & \mathbf{B} & \frac{\mathbf{C}=}{\mathbf{A}+\mathbf{B}} & \frac{\mathbf{D}=}{\mathbf{A}+\mathbf{B}} & \begin{array}{c} \mathbf{Y}= \\ \mathbf{C}+\mathbf{D} \end{array} \\ \hline 0 & 0 & 1 & 1 & 1 \\ \hline 0 & 1 & 0 & 0 & 0 \\ \hline 1 & 0 & 0 & 0 & 0 \\ \hline 1 & 1 & 0 & 0 & 0 \\ \hline \end{array}$ $\therefore$ The output of the given combination is same as that of a NOR gate.

Asked in: MHT CET 2023 (14 May Shift 2)

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