
The order of reactivity of the following alcohols towards conc. HCl is

- $\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}$
- $\quad \mathrm{I}>\mathrm{III}>\mathrm{II}>\mathrm{V}$
- $\quad$ IV $>\mathrm{III}>\mathrm{II}>\mathrm{I}$
- $\quad$ IV $>\mathrm{III}>\mathrm{I}>\mathrm{II}$
Solution

Remember that presence of electron-withdrawing group intensifies i.e., destabilises the carbocation thus (i) and (ii) are less stable than (iii). Further (i) is less stable than (ii) because-I effect is more pronounced in (i) due to less distance between $\mathrm{F}$ and positive charge. Thus the stability order of the four carbocations and reactivity of their parent alcohols will be
$$
\mathrm{IV}>\mathrm{III}>\mathrm{II}>\mathrm{I}
$$ *
Asked in: JEE-TOPICTESTS-CHEMISTRY
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