The order and degree of the differential equation $\frac{d^2 y}{d x^2}=\sqrt{\frac{d y}{d x}}$ are respectively

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Aicharya · Accepted Answer

$\begin{aligned} & \frac{d^2 y}{d x^2}=\sqrt{\frac{d y}{d x}} \ & 	herefore \quad\left(\frac{d^2 y}{d x^2}ight)=\frac{d y}{d x} \ & 	herefore 	ext { order }=2 	ext { and degree }=2\end{aligned}$

The order and degree of the differential equation $\frac{d^2 y}{d x^2}=\sqrt{\frac{d y}{d x}}$ are…

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