The orange coloured compound formed when $\mathrm{H}_2 \mathrm{O}_2$ is added to $\mathrm{TiO}_2$ solution…
The orange coloured compound formed when $\mathrm{H}_2 \mathrm{O}_2$ is added to $\mathrm{TiO}_2$ solution acidified with conc $\mathrm{H}_2 \mathrm{SO}_4$ is
$\mathrm{Ti}_2 \mathrm{O}_3$
$\mathrm{H}_2 \mathrm{Ti}_2 \mathrm{O}_8$
$\mathrm{H}_2 \mathrm{TiO}_3$
$\mathrm{H}_2 \mathrm{TiO}_4$
Solution
When an acidified solution of $\mathrm{TiO}_2$ is treated with $\mathrm{H}_2 \mathrm{O}_2$, an intense yellow orange colour is obtained due to the formation of $\mathrm{H}_2 \mathrm{TiO}_4$.
$\mathrm{TiO}_2+\mathrm{H}_2 \mathrm{O}_2 \stackrel{\mathrm{H}_2 \mathrm{SO}_4}{\longrightarrow} \mathrm{H}_2 \mathrm{TiO}_4$
This reaction is used for detection of both $\mathrm{Ti}(\mathrm{IV})$ and $\mathrm{H}_2 \mathrm{O}_2$.