
The option(s) with correct sequence of reagents for the conversion of $\mathbf{P}$ to $\mathbf{Q}$ is(are) :

- i) Lindlar's catalyst, $\mathrm{H}_2$; ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$; iii) $\mathrm{NaBH}_4$; iv) $\mathrm{H}_3 \mathrm{O}^{+}$
- i) Lindlar's catalyst, $\mathrm{H}_2$; ii) $\mathrm{H}_3 \mathrm{O}^{+}$; iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$; iv) $\mathrm{NaBH}_4$
- i) $\mathrm{NaBH}_4$; ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$; iii) $\mathrm{H}_3 \mathrm{O}^{+}$; iv) Lindlar's catalyst, $\mathrm{H}_2$
- i) Lindlar's catalyst, $\mathrm{H}_2$; ii) $\mathrm{NaBH}_4$; iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$; iv) $\mathrm{H}_3 \mathrm{O}^{+}$
Asked in: JEE Advanced 2024 (Paper 2)