The octahedral complex of a metal ion $\mathrm{M}^{3+}$ with four monodentate ligands $L_{1}, L_{2}, L_{3}$…

The octahedral complex of a metal ion $\mathrm{M}^{3+}$ with four monodentate ligands $L_{1}, L_{2}, L_{3}$ and $L_{4}$ absorb wavelengths in the region of red, green, yellow and blue, respectively. The increasing order of ligand strength of the four ligands is:
  1. $\quad L_{4} < L_{3} < L_{2} < L_{1}$
  2. $\quad L_{1} < L_{3} < L_{2} < L_{4}$
  3. $\quad L_{3} < L_{2} < L_{4} < L_{1}$
  4. $\quad L_{1} < L_{2} < L_{4} < L_{3}$

Solution

The energy of red light is less than that of violet light So energy order is Red \(<\) Yellow \(<\) Green \(<\) Blue The complex absorbs lower energy light lower will be its strength. So order of ligand strength is \(L_1 < L_3 < L_2 < L_4\)

Asked in: JEE-TOPICTESTS-CHEMISTRY

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