The numbers of turns in the primary and the secondary of a transformer are 1000 and 3000 respectively. If…

The numbers of turns in the primary and the secondary of a transformer are 1000 and 3000 respectively. If $80 \mathrm{~V}$ a.c. is applied to the primary coil of the transformer, then the potential difference per turn of the secondary coil would be
  1. $240 \mathrm{~V}$
  2. $2400 \mathrm{~V}$
  3. $0.24 \mathrm{~V}$
  4. $0.08 \mathrm{~V}$

Solution

$\frac{E_p}{E_s}=\frac{N_p}{N_s}$ $\frac{80}{E_{\mathrm{s}}}=\frac{1000}{3000}$ $E_s=240 \mathrm{~V}$ $\therefore \quad E_{\mathrm{s}}$ per turn $=\frac{240}{3000}=0.08 \mathrm{~V}$

Asked in: MHT CET 2023 (13 May Shift 2)

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