The number of ways of getting a sum 16 on throwing a dice four times is______

The number of ways of getting a sum 16 on throwing a dice four times is______

Solution

$\begin{aligned} & \left(x^1+x^2 \ldots+x^6\right)^4 \\ & x^4 \cdot\left(\frac{1-x^6}{1-x}\right)^4 \\ & x^4 \cdot\left(1-x^6\right)^4 \cdot(1-x)^{-4} \\ & x^4\left[1-4 x^6+6 x^{12} \ldots .\right]\left[(1-x)^{-4}\right] \\ & \left(x^4-4 x^{10}+6 x^{16} \ldots\right)(1-x)^{-4} \\ & \left(x^4-4 x^{10}+6 x^{16}\right)\left(1+{ }^{15} C_{12} x^{12}+{ }^9 C_6 x^6 \ldots .\right) \\ & \left({ }^{15} C_{12}-4 \cdot{ }^9 C_6+6\right) x^{16} \\ & \left({ }^{15} C_3-4 \cdot{ }^9 C_6+6\right) \\ & =35 \times 13-6 \times 8 \times 7+6 \\ & =455-336+6 \\ & =125\end{aligned}$

Asked in: JEE Main 2024 (05 Apr Shift 1)

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