The number of ways of distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is

The number of ways of distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is
  1. 5
  2. ${ }^8 C_3$
  3. $3^8$
  4. 21

Solution

Number of balls $=8$ number of boxes $=3$ Hence number of ways $={ }^7 C_2=21$.

Asked in: JEE Main 2004

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