The number of ways of arranging 8 men and 4 women around a circular table such that no two women can sit…
The number of ways of arranging 8 men and 4 women around a circular table such that no two women can sit together is
$8 !$
$4 !$
$8 ! 4 !$
$7 !{ }^8 P_4$
Solution
The number of ways of arranging 8 men $=7$ !
The number of ways of arranging 4 women such that no two women can sit together $={ }^8 P_4$ $\therefore$ Required number of ways $=7 !^8 P_4$.