The number of ways of arranging 2 red. 3 white and 5 yellow roses of different sizes into a garland such…
The number of ways of arranging 2 red. 3 white and 5 yellow roses of different sizes into a garland such that no two yellow roses come together is
2880
144
1440
288
Solution
Given 2 Red, 3 White and 5 Yellow roses.
$\Rightarrow \text { Total }=10 \text { roses }$
$\because$ Number of ways of arranging 2 Red and 3 White roses
$=(5-1)!=4!$
So, required number of ways
$=\frac{4!\times 5!}{2}=\frac{24 \times 120}{2}=1440 .$