The number of ways in which 6 men and 5 women can dine at a found table if no two women are to sit together…
The number of ways in which 6 men and 5 women can dine at a found table if no two women are to sit together is given by
$7 \times 5$
$6 \times 5$
30
$5 \times 4$
Solution
No.of ways in which $6 \mathrm{~mm}$ can be arranged at a round table $=(6-1)$ ! Now women can be arranged in 6 ! ways.
Total number of ways $=6 ! \times 5$ !