The number of ways in which 5 boys and 4 girls sit around a circular tables. So, that no two girls sit…
The number of ways in which 5 boys and 4 girls sit around a circular tables. So, that no two girls sit together is
- $5 ! 4 !$
- $3 ! 3 !$
- $5 !$
- $4 !$
Solution
Number of ways in which the boys can be arranged $=4$ !
Number of ways in which girls alternately arranged $=5$ !
Total number of ways $=5 ! 4 !$
Asked in: AP EAMCET 2001
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