The number of ways in which   5 boys and 3 girls can be seated on a round table if a particular boy B 1…

The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy B1 and a particular girl G1 never sit adjacent to each other, is:
  1. 7!
  2. 5×6!
  3. 6×6!
  4. 5×7!

Solution

Number of ways = Total - when B1 & G1 sit together

Total ways in which 5 boys+3 girls=8 people can be arranged is 7!

Now, when B1 & G1 sit together the number of ways (other 6and B1G1 grouped together) is 6!×2!

Hence, the required numer of ways is 7!-6!2!=5×6!

Asked in: JEE Main 2017 (09 Apr Online)

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