The number of values of ' $c$ ' for which the line $y=4 x+c$ touches the ellipse $\frac{x^2}{4}+\frac{y^2}{1}=1$ is

Question

Aicharya · Accepted Answer

The possible value of ' $c$ ' for which the line $y=4 x+c$ touches the ellipse $\frac{x^2}{4}+\frac{y^2}{1}=1$ is $c= \pm \sqrt{4 	imes 4+1}= \pm 3$

The number of values of ' $c$ ' for which the line $y=4 x+c$ touches the ellipse…