The number of turns in primary and secondary coils of a transformer is 50 and 200 respectively. If the…

The number of turns in primary and secondary coils of a transformer is 50 and 200 respectively. If the current in the primary coil is $4 \mathrm{~A}$, then the current in the secondary coil is
  1. $1 \mathrm{~A}$
  2. $2 \mathrm{~A}$
  3. $4 \mathrm{~A}$
  4. $5 \mathrm{~A}$

Solution

In a transformer $ \begin{array}{rlrl} & & \frac{N_P}{N_S} & =\frac{I_S}{I_P} \\ & \frac{50}{200} & =\frac{I_S}{4} \\ & I_S & =1 \mathrm{~A} \end{array} $

Asked in: AP EAMCET 2008

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