The number of solutions of the equation…
- 2
- 3
- 1
- 4
Solution
$\begin{aligned}
& \left\{9 \alpha^2-9 \alpha+2\right\}\left\{2 \alpha^2-7 \alpha+3\right\}=0 \\ & (3 \alpha-2)(3 \alpha-1)(\alpha-3)(2 \alpha-1)=0 \\ & \alpha=\frac{1}{3}, \frac{1}{2}, \frac{2}{3}, 3 \\ & x=9,4, \frac{9}{4}, \frac{1}{9}
\end{aligned}$
So, no. of solutions $=4$ ,
Asked in: JEE Main 2025 (29 Jan Shift 1)