The number of solutions, of the equation e sin x − 2 e − sin x = 2 is

The number of solutions, of the equation esinx2esinx=2 is
  1. 2
  2. more than 2
  3. 1
  4. 0

Solution

Let, esinx=t

t-2t=2

t2-2t-2=0

t2-2t+1=3

t-12=3

t=1±3

t2.73, -0.73not possible

t2.73

esinx2.73

sinxloge2.73

sinx>1Not possible

So no solutions will be possible for the given equation.

Asked in: JEE Main 2024 (31 Jan Shift 2)

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