The number of solutions of the equation 32 tan 2 x + 32 sec 2 x = 81 ,   0 ≤ x ≤ π 4…

The number of solutions of the equation 32tan2x+32sec2x=81, 0xπ4 is :
  1. 0
  2. 2
  3. 1
  4. 3

Solution

Given, 32tan2x+32sec2x=81,     0xπ4

32tan2x+321+tan2x=81

32tan2x+32.32tan2x=81

33×32tan2x=81

32tan2x=2711

tan2x=ln322711
tanx=ln3227110,1
One solution in 0,π4

Asked in: JEE Main 2021 (31 Aug Shift 2)

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