The number of solutions of the equation 2 θ - cos 2 θ + 2 = 0 in R is equal to ______.

The number of solutions of the equation 2θ-cos2θ+2=0 in R is equal to ______.

Solution

2θ-cos2θ+2=0

⇒ 2θ+2=cos2θ

As per the graph drawn there is only one point of intersection, so only one solution of the given equation.

Asked in: JEE Main 2022 (29 Jun Shift 1)

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