The number of solutions for the equation $x^2-5|x|+6=0$ is .........
The number of solutions for the equation $x^2-5|x|+6=0$ is .........
- 4
- 3
- 2
- 1
Solution
Given equation
$
\begin{aligned}
& x^2-5|x|+6=0 \\
& \Rightarrow \quad|x|^2-5|x|+6=0 \\
& \Rightarrow \quad(|x|-3)(|x|-2)=0 \\
& \Rightarrow \quad|x|=2 \text { or } 3 \\
& \Rightarrow \quad x= \pm 2, \pm 3 \\
&
\end{aligned}
$
$\therefore$ There are 4 solutions
Asked in: AP EAMCET 2020 (22 Sep Shift 1)
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