The number of six digit natural numbers that can be formed with the digits $2,3,4,0,5,6,7,8$ is
- $7 \times 2^{12}$
- $7 \times 2^9$
- $7 \times 2^6$
- $7 \times 2^{15}$
Solution

So, number of 6 digit number $\begin{aligned} & =7 \times 8 \times 8 \times 8 \times 8 \times 8 \\ & =7 \times 2^{15} \end{aligned}$
Asked in: AP EAMCET 2023 (15 May Shift 2)