The number of roots of the equation, 81 sin 2 x + 81 cos 2 x = 30 in the interval 0 , π is equal to :

The number of roots of the equation, 81sin2x+81cos2x=30 in the interval 0,π is equal to :
  1. 3
  2. 4
  3. 8
  4. 2

Solution

81sin2x+81cos2x=30

81sin2x+81181sin2x=30

81sin2x=t

t+81t=30

t2-30t+81=0

t-3t-27=0

81sin2x=31 or  81sin2x=33

34sin2x=31  or   34sin2x=33

sin2x=14  or  sin2x=34

  

Hence, total 4 solution.

Asked in: JEE Main 2021 (16 Mar Shift 1)

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