The number of relations on the set $\mathrm{A}=\{1,2,3\}$ containing at most 6 elements including $(1,2)$,…
Solution
& A=\{1,2,3\} \\ & (1,1),(2,2),(3,3),(1,2) \in R
\end{aligned}$
Remaining elements are
$(2,1),(2,3),(1,3),(3,1),(3,2)$
(1) If relation contains exactly 4 elements = 1 way
(2) if relation contains exactly 5 elements
It can be $(1,3),(3,2) \Rightarrow 2$ ways
(3) If relation contain exactly 6 elements
It can be $((2,3),(1,3)),((1,3),(3,2)),((3,1),(3,2))$
$\Rightarrow 3$ ways.
Total $=6$ ways
Asked in: JEE Main 2025 (07 Apr Shift 1)