The number of real values of $m$ so that the equation $x^2+(2 m+1) x+m=0$ has equal roots is

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Aicharya · Accepted Answer

$x^2+(2 m+1) x+m=0$ For equal roots, $\begin{aligned} & \mathrm{D}=0 \ & (2 m+1)^2-4 m=0 \ & 4 m^2+1+4 m-4 m=0 \ & 4 m^2+1=0 \ & m^2=-1 / 4 \ & m^2>0\end{aligned}$ No real values of $m$ exist.

The number of real values of $m$ so that the equation $x^2+(2 m+1) x+m=0$ has equal roots is

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