The number of possible optical isomers for the complexes ${M A}_{2} B_{2}$ with $s p^{3}$ and $d s p^{2}$ hybridized metal atom, respectively, is:
Note: $A$ and $B$ are unidentate neutral and unidentate monoanionic ligands, respectively.

Question

The number of possible optical isomers for the complexes

{M A}_{2} B_{2}

with

s p^{3}

and

d s p^{2}

hybridized metal atom, respectively, is:
Note:

A

and

B

are unidentate neutral and unidentate monoanionic ligands, respectively.

Aicharya · Accepted Answer

If the complex MA 2 B 2 &#8201; is &#8201; &#8201;sp 3 hybridised then the shape of this complex is tetrahedral this structure is optically inactive due to the presence of plane of symmetry Optical isomers = 0 (b) If the complex MA 2 B 2 &#8201; is &#8201; &#8201; dsp 2 hybridised then the shape of this complex is square planar. Both isomers are optically inactive due to the presence of plane of symmetry. Optical isomers = 0

The number of possible optical isomers for the complexes M A 2 B 2 with s p 3 and d s p 2 hybridized metal…

Solution