The number of photons per second on an average emitted by the source of monochromatic light of wavelength…

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3×10-3 W will be :h=6.6×10-34 J s
  1. 1018
  2. 1017
  3. 1016
  4. 1015

Solution

Energy of each photon, E=hcλ

⇒E=6.6×10-34×3×108600×10-9

⇒E=3.3×10-19 J

Number of photons emitted per second, N=PE

⇒N=3.3×10-33.3×10-19

⇒N=1016

Asked in: NEET 2021

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